For a buffer with a pKa of 4.76, if the pH equals the pKa, what is the ratio of salt to weak acid?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $9.99Unlock all

Prepare for the Bishop Clinical Chemistry Test. Study with flashcards and multiple choice questions, each question has hints and explanations. Get ready for your exam!

Multiple Choice

For a buffer with a pKa of 4.76, if the pH equals the pKa, what is the ratio of salt to weak acid?

Explanation:
The key idea is the Henderson–Hasselbalch relationship, which links pH to the ratio of conjugate base to weak acid: pH = pKa + log([A-]/[HA]). If pH equals pKa, the log term must be zero, so [A-]/[HA] = 1. That means the salt (conjugate base form) and the weak acid form are present in equal amounts, giving a 1:1 ratio.

The key idea is the Henderson–Hasselbalch relationship, which links pH to the ratio of conjugate base to weak acid: pH = pKa + log([A-]/[HA]). If pH equals pKa, the log term must be zero, so [A-]/[HA] = 1. That means the salt (conjugate base form) and the weak acid form are present in equal amounts, giving a 1:1 ratio.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy